Weight and stopping distance
#13
RE: Weight and stopping distance
it's a simple concept of physics, in a perfect world, they would be the same, due to their different masses, the pads have the same coef. friction, the smaller car will result in a quicker deacceleration since it doesn't have to work as hard to stop the extra weight that the larger vehicle is carrying.
just try to imagine a civic having the brakes of a tractor trailer, which one would stop quicker, the tractor trailer or the civic?
just try to imagine a civic having the brakes of a tractor trailer, which one would stop quicker, the tractor trailer or the civic?
#16
RE: Weight and stopping distance
ORIGINAL: civicexracer
in a perfect world such as math/physics, probably so...but there are so many other things to take into account.
in a perfect world such as math/physics, probably so...but there are so many other things to take into account.
#17
RE: Weight and stopping distance
ORIGINAL: mybrokenblinker
the point of this is theoretica...and ej6buddy...trust me, the answer is that they are equal. The smaller one doesn't have a quicker decceleration because even though it is stopping less weight, it's frictional force is less. therefore the trailer and civic would stop in the same distance.
ORIGINAL: civicexracer
in a perfect world such as math/physics, probably so...but there are so many other things to take into account.
in a perfect world such as math/physics, probably so...but there are so many other things to take into account.
#18
RE: Weight and stopping distance
sorry i meant the frictional force between the ground and wheel is less on the lighter car so that even though it has less weight to deccelerate, it has less force to do it with.
#20
RE: Weight and stopping distance
wait, were you trying to say that the strength of the brakes are proportionate to the vehicle weight itself, or were you just implying that they are just equal.
and since you said that it was because of the frictional force via road/tire, even if both cars were to lock up the brakes, the momentum due to the larger vehicle will carry a greater distance (since you are neglecting weight transfer as well as spring weight)
and the reason you're getting varied answers is b/c you aren't supplying them with sufficient information on the scenario. i.e. frictional coef., tread sa, is the coef b/t brake brake and rotor same, are the rotor diameters equal b/t cars, etc.
and since you said that it was because of the frictional force via road/tire, even if both cars were to lock up the brakes, the momentum due to the larger vehicle will carry a greater distance (since you are neglecting weight transfer as well as spring weight)
and the reason you're getting varied answers is b/c you aren't supplying them with sufficient information on the scenario. i.e. frictional coef., tread sa, is the coef b/t brake brake and rotor same, are the rotor diameters equal b/t cars, etc.